A 0.24 g sample of compound of oxygen and boron was found by analysis to contain 0.096 g of boron and 0.144 g of oxygen. Calculate the percentage composition of the compound by weight.

Answer :

Mass of boron as given = 0.096 g

Mass of oxygen as given  = 0.144 g

Mass of sample as given   = 0.24 g

∴  Percentage of boron by weight in the compound = (0.096 ÷ 0.24 )  x 100 = 40%

∴  Percentage of oxygen by weight in the compound = (0.144 ÷ 0.24)  x 100 = 60%

This is an answered question from Chapter 3. Atoms And Molecules of CBSE Class 9th Science

Check for Complete Exercise Solution for Chapter 3. Atoms And Molecules | CBSE Class 9th Science