Answer :
Suppose the percentage of
16 | |
X in given sample = x | |
8 |
:. The percentage of
18 | |
X in given sample = 100-x | |
8 |
As given average atomic mass of a sample of an element X = 16.2 u
=> (16 × x /100) + [18 × (100-x) /100] = 16.2
=> (16x + 1800-18x) / 100 = 16.2
=> (16x + 1800-18x) = 16.2 × 100
=> -2x + 1800 = 1620
=> -2x = 1620-1800
= -2x = -180
=> x = 90
:. The percentage of
16 | |
X in given sample = x = 90 | |
8 |
:. The percentage of
16 | |
X in given sample = 100-x =100-90 = 10 | |
8 |
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